PSAT Ratios and Unit Rates: Label Both Quantities

Tell a same-unit ratio from a unit rate with an original table, unit labels, and checked practice. Scale a rate when every row matches, and pause when a fixed fee changes the average.

Write both quantities as a fraction and keep their units attached. When the units match, simplify that ratio and preserve the order the question names. When the units differ, the comparison is a rate. Dividing gives the unit rate: the amount of the first quantity for exactly 1 unit of the second. Multiply by a new count after every row in the table produces that same unit rate.

College Board’s PSAT/NMSQT Math overview places ratios, rates, proportional relationships, and units in Problem-Solving and Data Analysis, and it includes understanding and applying a unit rate. The examples below are original Kibo practice. The counts and prices are hypothetical.

Match the units before you simplify

OpenStax’s ratios and rates lesson separates three comparisons. A ratio compares two quantities measured in the same unit. A rate compares quantities in different units and keeps both units visible. A unit rate is a rate whose denominator is exactly 1 unit.

What to write down before calculating
NameUnitsResult to report
RatioThe same unitA simplified fraction, or a:ba:b, in the named order
RateDifferent unitsA fraction that still shows both units
Unit rateDifferent units, denominator 1How much of the numerator there is for each 1 of the denominator

A mix of 33 cable ties to 22 battery clips can stay as 3:23:2 or as 32\frac{3}{2}. Leave the improper fraction in that form so both parts remain visible. A pace of 152\frac{15}{2} labels for each 11 minute is a unit rate: the denominator is 11 minute, and 152\frac{15}{2} is the number of labels.

Worked ratio: one kit table

A robotics club packs identical kits and uses every item in this table.

Supplies used for the kits
ItemCount
Cable ties3636
Battery clips2424

The question asks for the ratio of cable ties to battery clips. Cable ties go in the numerator because they are named first.

3624=32\frac{36}{24}=\frac{3}{2}

Divide the numerator and the denominator by 1212. The simplified ratio is 3:23:2: 33 cable ties for every 22 battery clips. The club can pack 1212 kits, because 36÷3=1236\div3=12 and 24÷2=1224\div2=12. Each kit gets 33 ties and 22 clips, and 12×3=3612\times3=36 while 12×2=2412\times2=24.

A part-to-whole comparison changes the second quantity. All pieces together are 36+24=6036+24=60. The ratio of cable ties to all pieces is 3660=35\frac{36}{60}=\frac{3}{5}.

  • 3:23:2 compares ties with clips and matches the question.
  • 2:32:3 compares clips with ties. It reverses the named order.
  • 3:53:5 compares ties with all 6060 pieces.

Worked unit rate: a steady printing pace

The same club prints labels at a steady pace. Each row is a total from the start, measured in minutes and labels.

Labels printed from the start
MinutesLabels printedLabels per minute
443030304=152\frac{30}{4}=\frac{15}{2}
886060608=152\frac{60}{8}=\frac{15}{2}
121290909012=152\frac{90}{12}=\frac{15}{2}

Every row gives 152\frac{15}{2} labels per minute, or 7.57.5 labels for each 11 minute. The matching unit rate in the other direction is 430=215\frac{4}{30}=\frac{2}{15} minute per label.

For 1010 minutes, multiply the label rate by the new time: 152×10=75\frac{15}{2}\times10=75 labels. For 4545 labels, divide by that same rate: 45152=6\frac{45}{\frac{15}{2}}=6 minutes. The other unit rate agrees: 45×215=645\times\frac{2}{15}=6.

The product 45×152=6752=337.545\times\frac{15}{2}=\frac{675}{2}=337.5 multiplies a label count by labels per minute. Use that product when the 4545 is a number of minutes. In this question 4545 is already a label count, and the time answer is 66 minutes.

Convert both lengths, then compare again

A poster is 1.51.5 feet high and 2424 inches wide. The ratio of height to width needs one shared unit. OpenStax converts 11 foot to 1212 inches before comparing two lengths.

1.5×12=18and1824=341.5\times12=18\quad\text{and}\quad\frac{18}{24}=\frac{3}{4}

In feet, the width is 2412=2\frac{24}{12}=2. Then 1.52=34\frac{1.5}{2}=\frac{3}{4}. Both setups give the ratio 3:43:4.

The mixed comparison 1.524=116\frac{1.5}{24}=\frac{1}{16} puts feet over inches. It describes a different pair of measurements. After both lengths use inches, or both use feet, the poster ratio is 3:43:4.

A setup fee changes the average

A shop charges $3\$3 to start a print job and $0.40\$0.40 for each label. For 3030 labels, 0.40×30=120.40\times30=12, so the bill is 3+12=153+12=15 dollars. The average is 1530=0.50\frac{15}{30}=0.50 dollars per label.

For 6060 labels, 0.40×60=240.40\times60=24, so the bill is 3+24=273+24=27 dollars. The average is 2760=0.45\frac{27}{60}=0.45 dollars per label. The fraction check is the same arithmetic: 0.40=250.40=\frac{2}{5}, and 25×60=24\frac{2}{5}\times60=24.

Those averages differ, so the 3030-label average describes that bill. Doubling $15\$15 produces $30\$30. The 6060-label bill is $27\$27. The $3\$3 gap is a second copy of the setup fee.

Labels added after the job has started still cost $0.40\$0.40 each: 27−1560−30=1230=0.40\frac{27-15}{60-30}=\frac{12}{30}=0.40. Use $0.40\$0.40 per label for one more label. Use $0.50\$0.50 per label as the description of the 3030-label total.

A budget limit on a setup charge plus a per-item price is a linear inequality. Our PSAT inequalities guide works through that kind of total and checks the next whole number.

Scale a ratio with the same factor

The club keeps 33 cable ties for every 22 battery clips and will use 4242 cable ties. How many clips does that mix need?

Because 3×14=423\times14=42, multiply the clip count by the same 1414: 2×14=282\times14=28. The equivalent fraction is 4228=32\frac{42}{28}=\frac{3}{2}.

Multiplying 42×3242\times\frac{3}{2} gives 6363. That product is the tie count for 4242 clips, which reverses the named order. The clip count for 4242 ties is 2828.

The equation 32=42c\frac{3}{2}=\frac{42}{c} uses the same balance as a linear equation. Our guide to equations with variables on both sides shows how to apply one operation to both sides and then substitute the result.

Try three original questions

Label the units and the requested order before you choose an answer.

  1. A bin has 1818 red pens and 3030 blue pens. What is the simplest ratio of red pens to blue pens?
    • A. 3:53:5
    • B. 5:35:3
    • C. 3:83:8
    • D. 9:159:15
  2. A walker covers 2.42.4 kilometers in 3232 minutes at a steady pace. Which value is the distance covered in 1515 minutes?
    • A. 98\frac{9}{8} kilometers
    • B. 5.125.12 kilometers
    • C. 403\frac{40}{3} minutes
    • D. 340\frac{3}{40} kilometer
  3. A reading log records pages finished from the start of a study block.

    Pages recorded during the study block
    HoursPages
    225050
    449090
    66130130

    Which statement matches every row?

    • A. The page total is 2525 pages per hour at every row.
    • B. The page total rises by 2020 pages for each additional hour, and p=20h+10p=20h+10 matches every row.
    • C. Six hours at the first row’s average predicts the table’s 130130 pages.
    • D. The quotients 502\frac{50}{2}, 904\frac{90}{4}, and 1306\frac{130}{6} are equal.
Show answers and checks
  1. Choice A, 3:53:5. Simplify 1830\frac{18}{30} by dividing by 66. The red-to-all ratio is a different comparison: 18+30=4818+30=48 and 1848=38\frac{18}{48}=\frac{3}{8}.

    • Choice B, 5:35:3, compares blue pens with red pens.
    • Choice C, 3:83:8, compares red pens with all 4848 pens.
    • Choice D, 9:159:15, divides by 22 and still has a common factor of 33. Dividing again gives 3:53:5.
  2. Choice A, 98\frac{9}{8} kilometers, or 1.1251.125 kilometers. First write 2.4=1252.4=\frac{12}{5}. The pace is 125÷32=340\frac{12}{5}\div32=\frac{3}{40} kilometer per minute, so 1515 minutes cover 340×15=98\frac{3}{40}\times15=\frac{9}{8} kilometers. The other unit rate agrees: 32125=403\frac{32}{\frac{12}{5}}=\frac{40}{3} minutes per kilometer, and 15÷403=9815\div\frac{40}{3}=\frac{9}{8}.

    • Choice B multiplies the inverted time fraction by the full distance: 3215×125=12825=5.12\frac{32}{15}\times\frac{12}{5}=\frac{128}{25}=5.12 kilometers. The 1515-minute piece is 1532\frac{15}{32} of 2.42.4 kilometers.
    • Choice C, 403\frac{40}{3} minutes, is the time for 11 kilometer.
    • Choice D, 340\frac{3}{40} kilometer, is the distance for 11 minute.
  3. Choice B. From 22 to 44 hours the log adds 4040 pages, and from 44 to 66 hours it adds 4040 pages again. That is 2020 pages for each additional hour. The equation p=20h+10p=20h+10 matches the rows: 20(2)+10=5020(2)+10=50, 20(4)+10=9020(4)+10=90, and 20(6)+10=13020(6)+10=130.

    • Choice A fits the first row only. 502=25\frac{50}{2}=25, while 904=22.5\frac{90}{4}=22.5 and 1306=653\frac{130}{6}=\frac{65}{3}.
    • Choice C gives 25×6=15025\times6=150 pages. The table shows 130130 pages at 66 hours.
    • Choice D asks those three quotients to be equal. They are 2525, 22.522.5, and 653\frac{65}{3}.

Check the labels before you submit

  • Write both units beside the fraction before you simplify.
  • Place the first quantity named in the question in the numerator.
  • Check a second row before you scale a unit rate to a new count.
  • For a length ratio, convert both measurements, then repeat the simplification in the other unit.

If an answer misses, record whether the order, the units, or the decision to scale caused it. Our practice error log turns that note into a next step. When the question asks for a percent increase or decrease, our percent-change guide shows which amount is the reference.

Try a free PSAT practice question with Kibo.

Prepared with AI assistance. Original examples were checked with separate exact calculations; no human review is claimed. Sources checked November 10, 2026. PSAT/NMSQT is a registered trademark of College Board and National Merit Scholarship Corporation. Kibo is not affiliated with or endorsed by either organization.