SAT Percent Word Problems: Name the Amount the Percent Describes

Write a percent equation from the amount it describes, and see why the same increase and decrease rates leave the starting amount smaller. Four original questions include checked choices.

In a percent equation, the percent belongs to one specific amount. Write that amount down before you multiply. For a rate rr written as a decimal, an increase of that amount uses the factor 1+r1+r, and a decrease uses the factor 1−r1-r. If a positive rate rr increases an amount and the same rate then decreases the result, the combined factor is (1+r)(1−r)=1−r2(1+r)(1-r)=1-r^{2}. Whenever 0<r<10<r<1, that product is less than 11, so the final amount is smaller than the amount you started with.

College Board’s SAT Math overview lists Problem-Solving and Data Analysis among the four math areas and says approximately 30% of Math section questions are set in context. In the Student Question Bank, the percentages skill in that area includes discounts, interest, taxes, and tips, and the relationship between a percent increase or decrease and a growth factor. OpenStax Elementary Algebra finds a percent increase or a percent decrease by dividing the change by the original amount. The ticket, hoodie, fund, and yearbook examples below are original Kibo practice.

Match each phrase with its factor

A campus club sells a concert ticket for $40\$40. The processing charge is 6%6\% of the ticket price. The 6%6\% describes the $40\$40 ticket, so the charge is 0.06×40=2.400.06\times 40=2.40 dollars. The total is 40+2.40=42.4040+2.40=42.40 dollars, which is the same as 40×1.0640\times 1.06. The 11 in 1.061.06 keeps the ticket price, and the 0.060.06 adds the charge.

Three phrases that all use a $40 ticket
PhraseFactorResult
6%6\% of $40\$400.060.06$2.40\$2.40, the charge only
6%6\% more than $40\$401.061.06$42.40\$42.40, the ticket plus the charge
6%6\% less than $40\$400.940.94$37.60\$37.60

The factor 1.061.06 is the growth factor for a 6%6\% increase of the ticket price. 1−0.06=0.941-0.06=0.94, so a 6%6\% decrease of the same $40\$40 ticket gives 40×0.94=37.6040\times 0.94=37.60 dollars.

Divide when the starting price is the unknown

After a 25%25\% increase, a club hoodie costs $45\$45. Let PP be the price in dollars before the increase. The 25%25\% describes PP, so

1.25P=451.25P=45

P=451.25=36P=\frac{45}{1.25}=36

The price before the increase was $36\$36. From the definition of a 25%25\% increase, 36×0.25=936\times 0.25=9 and 36+9=4536+9=45. The factor check is 36×1.25=4536\times 1.25=45.

Two calculations that start from $45\$45 answer different questions. 45×1.25=56.2545\times 1.25=56.25 adds 25%25\% of the new price. 45×0.75=33.7545\times 0.75=33.75 subtracts 25%25\% of the new price. The price before a 25%25\% increase is the new price divided by 1.251.25.

The linear-equation guide shows how to apply one operation to both sides while you isolate an unknown. The PSAT percent-change guide recovers a price after a discount. The same reference idea applies here when the starting amount of an increase is the unknown.

The same rate up and down leaves a smaller amount

A club fund holds $500\$500. The balance increases by 10%10\%, and then it decreases by 10%10\%.

  • The increase uses $500\$500: 500×1.10=550500\times 1.10=550. It adds 500×0.10=50500\times 0.10=50 dollars.
  • The decrease uses $550\$550: 550×0.90=495550\times 0.90=495. It removes 550×0.10=55550\times 0.10=55 dollars.
  • Together, 500×1.10×0.90=495500\times 1.10\times 0.90=495.

For a rate rr with 0<r<10<r<1,

(1+r)(1−r)=1−r2(1+r)(1-r)=1-r^{2}

Here r=0.10r=0.10, so the product is 1−0.01=0.991-0.01=0.99, and 500×0.99=495500\times 0.99=495. The fund finishes 500×0.01=5500\times 0.01=5 dollars below its start. The decrease removes $55\$55, while the increase added $50\$50, because the decrease uses the larger intermediate balance.

These two factors can be multiplied in either order. A 10%10\% decrease first gives 500×0.90=450500\times 0.90=450, and the following 10%10\% increase gives 450×1.10=495450\times 1.10=495. The intermediate balances are $450\$450 and $550\$550. The ending balance is $495\$495 on both paths.

A growth factor applied over several equal periods follows a different model. The exponential-growth guide separates that repeated factor from a single percent change.

Give each percent its own amount

A yearbook lists for $80\$80. The sale price is 20%20\% less than the list price. Shipping is 5%5\% of the sale price.

  1. The sale price uses the list price: 80×0.80=6480\times 0.80=64 dollars.
  2. Shipping uses the sale price: 64×0.05=3.2064\times 0.05=3.20 dollars.
  3. The total is 64+3.20=67.2064+3.20=67.20 dollars.

One product gives the same total: 80×0.80×1.05=80×0.84=67.2080\times 0.80\times 1.05=80\times 0.84=67.20. The 20%20\% describes the $80\$80 list price, and the 5%5\% describes the $64\$64 sale price.

Adding 5%5\% of the list price gives 64+4=6864+4=68. Subtracting the rates, 20%−5%=15%20\%-5\%=15\%, and 15%15\% off the list price is 80×0.85=6880\times 0.85=68. Both of those results use the list price for every percent. The stated shipping rule uses the sale price, so the total is $67.20\$67.20.

Try four original practice questions

Exactly one choice answers each question. The only charges are the ones named in the question.

  1. A notebook costs $25\$25. A sleeve for it costs 8%8\% of the notebook price. Which equation gives the total cost TT in dollars?

    • A. T=25+8T=25+8
    • B. T=0.08×25T=0.08\times 25
    • C. T=25×1.08T=25\times 1.08
    • D. T=25+0.08T=25+0.08
  2. After a 20%20\% increase, a jacket costs $54\$54. What was the price before the increase?

    • A. $43.20\$43.20
    • B. $45.00\$45.00
    • C. $64.80\$64.80
    • D. $34.00\$34.00
  3. A concession stand has 250250 bottles of water. The count increases by 20%20\%, then decreases by 20%20\%. How many bottles are there at the end?

    • A. 250250
    • B. 240240
    • C. 200200
    • D. 300300
  4. A yearbook lists for $60\$60. The sale price is 25%25\% less than the list price, and shipping is 8%8\% of the sale price. What is the total?

    • A. $45.00\$45.00
    • B. $48.60\$48.60
    • C. $49.80\$49.80
    • D. $64.80\$64.80
Show answers and checks
  1. Choice C. The sleeve is 8%8\% of $25\$25, so T=25×1.08=27T=25\times 1.08=27. The sleeve itself costs 0.08×25=20.08\times 25=2, and 25+2=2725+2=27.

    • Choice A is 25+8=3325+8=33, which treats 8%8\% as 88 dollars.
    • Choice B is 0.08×25=20.08\times 25=2, the sleeve price with the notebook price left out.
    • Choice D is 25+0.08=25.0825+0.08=25.08, which adds the decimal rate as dollars.
  2. Choice B. The 20%20\% describes the unknown starting price, so 1.20P=541.20P=54 and P=54/1.20=45P=54/1.20=45. Check: 45×0.20=945\times 0.20=9 and 45+9=5445+9=54. Also, 45×1.20=5445\times 1.20=54.

    • Choice A is 54×0.80=43.2054\times 0.80=43.20, a 20%20\% decrease of the new price.
    • Choice C is 54×1.20=64.8054\times 1.20=64.80, a 20%20\% increase of the new price.
    • Choice D is 54−20=3454-20=34, which treats 20%20\% as 2020 dollars.
  3. Choice B. 250×1.20=300250\times 1.20=300, and 300×0.80=240300\times 0.80=240. The combined factor is 1.20×0.80=0.96=1−0.2021.20\times 0.80=0.96=1-0.20^{2}, and 250×0.96=240250\times 0.96=240. The increase adds 5050 bottles. The decrease removes 20%20\% of 300300, which is 6060 bottles.

    • Choice A, 250250, is the result of treating the 20%20\% increase and the 20%20\% decrease as a return to the start.
    • Choice C is 250×0.80=200250\times 0.80=200, the decrease applied to the original count.
    • Choice D is 250×1.20=300250\times 1.20=300, the count after the increase only.
  4. Choice B. The sale price is 60×0.75=4560\times 0.75=45 dollars. Shipping is 45×0.08=3.6045\times 0.08=3.60 dollars, so the total is 45+3.60=48.6045+3.60=48.60. The combined factor is 0.75×1.08=0.810.75\times 1.08=0.81, and 60×0.81=48.6060\times 0.81=48.60.

    • Choice A is 60×0.75=4560\times 0.75=45, the sale price with shipping left out.
    • Choice C is 45+4.80=49.8045+4.80=49.80, from adding 8%8\% of the $60\$60 list price. It is also 60×0.8360\times 0.83, from taking 25%−8%=17%25\%-8\%=17\% off the list price.
    • Choice D is 60×1.08=64.8060\times 1.08=64.80, shipping on the list price with the sale left out.

Underline the amount, then write the factor

  • Copy the phrase that contains the percent and underline the amount it describes.
  • Use 1+r1+r for an increase of that amount and 1−r1-r for a decrease of that amount.
  • When the result is known and the starting amount is unknown, divide by the factor.
  • For two percents, update the reference after the first change, then apply the second factor.
  • Substitute the result into the original sentence.

If a result misses, record whether the reference, the factor, or the arithmetic needs another look. The practice error log keeps that note for a later recheck.

Try a free SAT practice question with Kibo and name the amount your percent describes before you calculate.

Prepared with AI assistance. The ticket totals, hoodie price, fund balances, yearbook totals, and every practice choice were checked with separate exact arithmetic. No human review or score improvement is claimed. Sources checked November 15, 2026. SAT is a registered trademark of College Board, which is not affiliated with or endorsing this guide.